MINSK, 21 January (BelTA) – Belarus number one Victoria Azarenka has celebrated her second victory at the ongoing Australian Open 2016, BelTA has learned.
The Belarusian, currently ranked 16th in the WTA rankings, took a solid win over World No.54 Danka Kovinic of Montenegro 6-1, 6-2 in 62 minutes. In the opener Victoria Azarenka secured the double bagel against World No.43 Alison Van Uytvanck of Belgium 6-0, 6-0 in just 49 minutes. The Belarusian will next take on Japan’s Naomi Osaka (World No.127). Victoria Azarenka is a two-time winner of the Australian Open (2012, 2013).
In the men’s doubles Max Mirnyi and his new partner Treat Huey of the Philippines progressed to the second round fighting through Alexander Bury of Belarus and Denis Istomin of Uzbekistan 7-6, 4-6, 7-6. The Belarusian-Philippine duet will next face Brazil’s Thomaz Bellucci and Marcelo Demoliner.
The $32 million Australian Open 2016 will finish on 31 January.